Matematika

Pertanyaan

berapakah hasik dari
x+y+z=75
x-y-z=5
x-4y+z=0
tolong yg bisa

1 Jawaban

  • x+y+z=75
    x-y-z=5
    x-4y+z=0

    .
    x+y+z=75
    x-y-z=5
    ------------- --
    2y + 2z = 70

    .
    x-y-z=5
    x-4y+z=0
    -------------- --
    3y - 2z = 5
    .

    2y + 2z = 70
    3y - 2z = 5
    ---------------- +
    5y = 75
    y = 75/5
    y = 15

    .
    2y + 2z = 70
    2(15) + 2z = 70
    30 + 2z = 70
    2z = 70 - 30
    2z = 40
    z = 40/2
    z = 20

    .
    x+y+z=75
    x + 15 + 20 = 75
    x + 35 = 75
    x = 75 - 35
    x = 40

    jadi x = 40, y = 15, z = 20

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