Jika sin x=1 per 3, hitunglah cos x dan tan x

1 = sin²x + cos²x
1 = (1/3)² + cos²x
cos²x = 1 - 1/9
cos²x = 8/9
cos x = 2akar2/3

tan x = sin x/cos x
tan x = (1/3)/(2akar2/3)
tan x = 1/2akar2
tan x = (1/4) akar2