Matematika

Pertanyaan

jika f(x) =2×pankat2-7 hitulanglah nilai f(2) f(3) f(4)dan f(5)

1 Jawaban

  • f(2) = 2×2²-7 = 1
    f(3) = 2×3²-7 =11
    f(4) = 2×4²-7 = 25
    f(5) = 2×5²-7 = 43
    #smoga membantu

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