lim ((2x²+1)(7x ∧4-14) x⇒√2
Matematika
fitri13rhf
Pertanyaan
lim ((2x²+1)(7x∧4-14)
x⇒√2
x⇒√2
1 Jawaban
-
1. Jawaban rizkafauziah
lim ((2x²+1)(7x∧4-14) = [(2(√2)^2 + 1)(7(√2)^4 - 14)]
x⇒√2 = [(2.2 + 1)(7.4 - 14)
= [ 5 . 14 ]
= 70