apabila R1=6 ohm R2 =2 ohm R3=8 ohm R4=9 ohm R5=3 ohm R6=3 ohm R7=3 ohm.tentukan hambatan penggantinya

kalau seri
Rs = R1+R2+R3+R4+R5+R6+R7
=6+2+8+9+3+3+3
=34 ohm

kalau paralel
1/Rp=1/R1+1/R2+1/R3+1/R4+1/R5+1/R6+1/R7
=1/6+1/2+1/8+1/9+1/3+1/3+1/3
=12/72+36/72+9/72+8/72+24/72+
' 24/72+24/72
=137/72
Rp =72/137
= 0,52 ohm