1-√3 tan (x+π/12)=0 untuk 0≤x≤2π gimana caranya?

1-√3.tan(x+π/12) = 0
tan(x+π/12) = 1/√3
tan(x+π/12) = tan 30°

x+π/12 = 30°
x + 15° = 30°
x = 15°

x = (15° , 195°)