integral ( x^2 + 1perX^2) dx=
Matematika
andro23
Pertanyaan
integral ( x^2 + 1perX^2) dx=
1 Jawaban
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1. Jawaban Anonyme
InTegraL
∫(x² + 1/x²) dx
= ∫(x² + x^-2) dx
= x³/3 + x^-1 /(-1) + C
= 1/3 x³ - 1/x + C