ubah ke dalam bentuk baku a.-5x + y = 4x - 12y + 6 5x - 5 (y + 1 ) = 2 (3y - 1 ) + 3x + 20 b.x/2 + y + 3/3 = 3 2x - 1 /3 - 4y + 1 /13 = 0

a.-5x+y=4x-12y+6
-5x-4x+y+12y-6=0
-9x+13y-6=0

5x-5(y+1)=2(3y-1)+3x+20
5x-5y-5=6y-2+3x+20
5x-5y-5=6y+3x+18
5x-3x-5y-6y-5-18=0
2x-11y-23=0

b.x/2+y+3/3=3
x/2+y+1=3(kedua ruas dikali 2)
x+2y+2=6
x+2y+2-6=0
x+2y-4=0

2x-1/3-4y+1/13=0(kedua ruas dikali 39)
78x-39/3-156y+39/13=0
78x-13-156y+3=0
78x-156y-10=0

2x-11y-23=0