Tolong ya, kak, 2 nomer aja..

Bab Fungsi


No 1)

f = {3,4,5,6,7}
f (x) = x^2 - 3x

f(3) = 3^2 - 3(3) = 9 - 9 = 0

f(4) = 4^2 - 3(4) = 16 - 12 = 4

f(5) = 5^2 - 3(5) = 25 - 15 = 10

f(6) = 6^2 - 3(6) = 36 - 18 = 18

f(7) = 7^2 - 3(7) = 49 - 21 = 28

HP= {0,4,10,18,28} ===> A

NO 2)
f(x) = 2/3 (x-1) + 5
f(7) = ?

f(7) = 2/3 (7-1) + 5
= 2/3 (6) + 5
= 12/3 + 5
= 4 + 5
= 9
= D