Matematika

Pertanyaan

nilai x yangemenuhi persamaan: 2^2x - 10. 2^x+1 = -64

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  • misalkan
    [tex]u=2^x\rightarrow u^2=2^{2x}[/tex]

    [tex]2^{2x}-10\times 2^{x+1}=-64\\u^2-10\times 2\times 2^x+64=0\\u^2-20u+64=0\\(u-16)(u-4)=0\\u_{1}=4\vee u_{2}=16\\x_{1}=^2\log{u_{1}}\vee x_{2}=^2\log{u_{2}}\\x_{1}=2\vee x_{2}=4[/tex]

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