A particle moves with a position vektor of r(t)=4t^i+(6t-2)j+3k.the vector of the particle at t=1second is

~Vektor Gaya~

Diketahui
r = 4t[tex]^{i}[/tex] + ( 6t - 2 ) + 3k
t = 1

Ditanya
Posisi vektor =__?

Jawab
karena t = 1 maka posisi vektor
r = 4[tex]^{2}[/tex] + ( 6t - 2 )j + 3k
r = 4. 1[tex]^{i}[/tex] + ( 6(1) - 2 )j + 3k
r = 4. 1[tex]^{i}[/tex] + 3j + 3k