tolong jawab sama caranya..

3√27^2x-1 = (³√1/243)^3x
3×27^((2x-1)/2) = ((1/243)^⅓)^3x
(3×(3³))^((2x-1)/2) = (1/243^⅓)^3x
3×3^(3×((2x-1)/2)) = (243^-½)^3x
3×3^(3(2x-1)/3) = 243^(-⅓×3x)
3^((2+6x-3)/2) = 3 ^(-5x)
(2+6x-3)/2 = -5x
x = 1/16