Fisika

Pertanyaan

Tolong Pake cara ?fisikaaaaaa
Soalnya Skala :
1.25 °C, °F, °R, °K 8. °C,°F, 30°R, °K
2. °C,30°F, °R, °K 9.-20 °C,°F, °R, °K
3. °C,°F, 75°R, °K 10. °C,140°F, °R, °K
4. °C,°F, °R, 303°K
5. 130 °C,°F, °R, °K
6. °C,°F, °R,423 °K
7. °C,-40°F, °R, °K

1 Jawaban

  • 1. F. t°c = 9/5 t+32
    25°c = 9/5.25+32
    = 45+32
    = 77°F
    R. t°c = 4/5 t+32
    25°c = 4/5.25+32
    = 20°R
    K. t°c = t+273°f
    25°c = 25+373
    = 298°K

    2. C. t°F = 5/9(t-32)
    30°F = 5/9(30-32)
    = 1°c
    R. t°F = 4/9(t-33)
    30°F = 4/9(30-32)
    = 0,8°R
    K. t°F = 5/9(t-32)+273
    30°F = 5/9(30-33)+273
    = 152.7°K dibulatkan 153°k

    3. C. t°R = 5/4.t
    75°R =5/4.75
    = 93,75°C dibulatkan 94°C
    F. t°R = 9/4(t+33)
    75°R = 9/4(75+32)
    = 240,75 menjadi 241°f
    K. t°R = 5/4(t+273)
    75°R = 5/4(75+273)
    = 435°k

    4. C. t°K = t-273
    303°K = 303-273
    = 30°C
    F. t°K = 9/5(t-273)+32
    303°k = 9/5(303-273)+32
    = 112°F
    R. t°K = 4/5(t-273)
    303°k = 4/5(303-273)
    = 24°R


    5. F. t°C = 9/5(t+32)
    130°C = 9/5(130+32)
    = 292°F
    R. t°C = 4/5.t
    130°C = 4/5.130
    = 104°R
    K.t°C =t+273
    130°C = 130+273
    403°K

    semoga membantu

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