²log √2 +²log 2√2-²log 16√3

2log akar 2 + 2log2 + 2log akar2 - 2log16 - 2log akar 3
= 1/2 + 1 +1/2 - 4 - 2 log akar 3
= - (2 + 2log akar 3)

kan 2 pangkat 1/2 = akar 2, makanya 2 log akar 2 bernilai 1/2

Logaritma

2 log √2 + 2 log 2√2 - 2 log 16√3
= 2 log (√2 . 2√2 / 16√3)
= 2 log (4 / 16√3)
= 2 log (1 / (4√3)
= 2 log (√3 / 12)
= 2 log 3^1/2 - 2 log 12
= 1/2 2 log 3 - 2 log 3 - 2 log 2²
= -1/2 2 log 3 - 2
= -2,477