Matematika

Pertanyaan

tolong jawab beserta caranya..thank you
tolong jawab beserta caranya..thank you

1 Jawaban

  • 3^(2x + 1) - 63 . 9^(x - 1) + 108 ≥ 0
    3 . 3^2x - 63 . 3^(2x - 2) + 108 ≥ 0
    3 . 3^2x - 63 . 3^2x /3^2 + 108 ≥ 0
    3 . 3^2x - 7 . 3^2x + 108 ≥ 0
    -4 . 3^2x ≥ -108
    3^2x ≤ -108/-4
    3^2x ≤ 3^3
    2x ≤ 3
    x ≤ 3/2

    Jawab : opsi C