Jika vektor a = 3i + 3j – 2k b = -i – 4j + 2k c = 2i + 2j + k hitunglah ax ( b dan c )

a = 3i + 3j – 2k
b = -i – 4j + 2k
c = 2i + 2j + k

a* ( b+ c )
= (3,3,-2) * (-1+2,-4+2,2+1)
= (3,3,-2) * (1,-2,3)
= 3(1) + 3(-2) + (-2)(3)
= 3 - 6 - 6
= -9 satuan