F(Q) =aQ+b F(3)=1 F(1)=-1 Tentukan nilai a dan b, rumus fungsi, nilai f(-2)

f(q) = aq + b

maka
f(3) = 3a + b
3a + b = 1

dan
f(1) = a + b
a+b=-1

lakukan eliminasi

3a+b = 1
a+b = -1
_______-
2a= 2
a = 1

maka
a+b = -1
1 + b = -1
b = -2

rumus fungsi :
f(q) = aq +b
f(q) = q - 2

nilai f(-2)
f(q) = q-2
f(-2) = -2 - 2
f(-2) = -4

semoga membantu :)