tolong kak dibantu pakai cara :)
Matematika
Clara991
Pertanyaan
tolong kak dibantu pakai cara :)
2 Jawaban
-
1. Jawaban Anonyme
x1 = y²
y = x2 - 2
x2 = y + 2
x1 = x2
y² = y + 2
y² - y - 2 =0
D = b²-4ac
D = (-1)²-4(1)(-2) = 9
Luas = D√D/(6a²)
Luas = 9√9/(6) = 27/6 = 4,5 -
2. Jawaban hendrisyafa
titik potong thd sb y
x = y²
x = y+2
x₁ = x₂
y² = y+2
y²-y-2 = 0
(y-2)(y+1) = 0
y = 2 and y = -1
batas bawah = -1
batas atas = 2
L = ∫ x₂ - x₁ dy
= ∫ y+2- y² dy
= ∫ -y² + y +2 dy
= -¹/₃ y ³+¹/₂y² + 2y
L = (-¹/₃.2³+¹/₂.2² + 2.2) - (-¹/₃.(-1)³+¹/₂.(-1)² + 2.(-1))
= (-⁸/₃+2+4) - (¹/₃+¹/₂-2)
= (¹⁰/₃) - (-⁷/₆)
= ²⁷/₆
= ⁹/₂
= 4 ¹/₂ satuan