Matematika

Pertanyaan

tolong kak dibantu pakai cara :)
tolong kak dibantu pakai cara :)

2 Jawaban

  • x1 = y²

    y = x2 - 2
    x2 = y + 2

    x1 = x2
    y² = y + 2
    y² - y  - 2 =0
    D = b²-4ac
    D = (-1)²-4(1)(-2) = 9
    Luas = D√D/(6a²)
    Luas = 9√9/(6) = 27/6 = 4,5
  • titik potong thd sb y

    x = y² 
    x = y+2
    x₁ = x₂
     y² = y+2
     y²-y-2 = 0
    (y-2)(y+1) = 0
     y = 2 and y = -1

    batas bawah = -1
    batas atas  = 2

    L = ∫ x₂ - x₁ dy
       = ∫ y+2- y² dy
       = ∫ -y² + y +2 dy
       = -¹/₃ y ³+¹/₂y² + 2y

    L   = (-¹/₃.2³+¹/₂.2² + 2.2) - (-¹/₃.(-1)³+¹/₂.(-1)² + 2.(-1))
         = (-⁸/₃+2+4) - (¹/₃+¹/₂-2)
         = (¹⁰/₃) - (-⁷/₆)
         = ²⁷/₆
         = ⁹/₂
         = 4 ¹/₂ satuan