Ini caranya gmn ya ?

(2log3 = a, 3log5= b. 6log40.
6log40 ='log40/log6
log(8.5) / log(2.3)
= (log8 + log5) / (log2 + log3)
= (log2^3 + log5) / (log2 + log3)
= (3.log2 + log5) / (log2 + log3) ganti bilangan pokok logariitma dengan 3, maka
= (3. 3log2 + 3log5) / (3log2 + 3log3)
= (3.1/a + b) / (1/a + 1)
= (3/a +b) / (1/a + 1)
= (3 +ab)/a / (a+1)/a
= (3+ab) / (a+1)