tentukan hasil ∫ (6x-3)  = √×^2-x+8 dx.

InTegraL

Misal :
u = x² - x + 8
du/dx =
du = (2x - 1) dx

∫(6x - 3)√(x² - x + 8) dx
= 3 ∫(2x - 1)(x² - x + 8)^1/2 dx
= 3 ∫u^1/2 du
= 3/(3/2) u^3/2 + C
= 2 (x² - x + 8)√(x² - x + 8) + C