Hitunglah nilai n pada operasi berikut! A.19×11-(1200:4):5=n B.650:26+13×19-125=n C.987-16×17+768:32=n Toling pakai carany yah:)
Matematika
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Pertanyaan
Hitunglah nilai n pada operasi berikut!
A.19×11-(1200:4):5=n
B.650:26+13×19-125=n
C.987-16×17+768:32=n
Toling pakai carany yah:)
A.19×11-(1200:4):5=n
B.650:26+13×19-125=n
C.987-16×17+768:32=n
Toling pakai carany yah:)
2 Jawaban
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1. Jawaban ACEls
A. (19x11)-(1200/4):5 = n
(19x11)-(300/5) = n
209 - 60 = n
n = 209-60
n = 149
B. (650:26)+(13x19)-125 = n
25 + 247 - 125 = n
n = 247 - 100
n = 147
C. 987-(16x17)+(768:32) = n
987 -(272) + (24) = n
n = 1011 - 272
n = 739 -
2. Jawaban nadjwaaqila
a. 19 x 11 - ( 1200 : 4 ) : 5 = ( 19 x 11 ) - ( 300 : 5 )
= 209 - 60
= 149 , n = 149
b. 650 : 26 + 13 x 19 - 125
= ( 650 : 26 ) + ( 13 x 19 ) - 125
= 25 + 247 - 125
= 147 , n = 147
c. 987 - 16 x 17 + 768 : 32
= 987 - ( 16 x 17 ) + ( 768 : 32 )
= 987 - 272 + 24
= 739 , n = 739
semoga bisa membantu :")