integral 3x √3x pangkat 2 + 1 dx

InTegraL

Misal :
u = 3x² + 1
du/dx = 6x
6x dx = du
2 . 3x dx = du
3x dx = 1/2 du

∫3x√(3x² + 1) dx
= ∫√u . 1/2 du
= 1/2 ∫u^1/2 du
= 1/2 (u^3/2) /(3/2) + C
= 1/3 u√u + C
= 1/3 (3x² + 1)√(3x² + 1) + C