Mohon dibantu cara penyelesaiannya

a.) (1) (2,0)(0,-4)
y-0 / -4-0 = x-2 / 0-2
y/-4 = x-2/-2
-4x + 8 = -2y
4x - 2y = 8
4x - 2y ... 8
(1,0) = 4(1) - 2(0) ... 8
4 ≤ 8
4x - 2y ≤ 8

(2) (3,0)(0,-3)
y-0 / -3-0 = x-3 / 0-3
y/-3 = x-3/-3
-3x + 9 = -3y
3x - 3y = 9
3x - 3y ... 9
(2,0) = 3(2) - 3(0) ... 9
6 ≤ 9
3x - 3y ≤ 9

(3) y ≤ 0

4x - 2y ≤ 8 (1)
3x - 3y ≤ 9 (2)
y ≤ 0 (3)