Tolong no.10-12 please urgent.
Matematika
Nidaanabilla22
Pertanyaan
Tolong no.10-12 please urgent.
1 Jawaban
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1. Jawaban RaffiFadhlurrahman
no. 10
TU:PR=TQ:PQ
4:6=(x+3):(4+(x+3))
2:3=(x+3):(x+7)
2(x+7)=3(x+3)
2x+14=3x+9
14-9=3x-2x
5=x
JADI, x = 5
no. 11
CB = x
CD = x+4
BA:DE=CB:CD
6:9=x:(x+4)
6(x+4)=9x
2(x+4)=3x
2x+8=3x
8=3x-2x
8=x
CD=x+4=8+4=12
no. 12
4:OC=8:10
4:OC=4:5
OC=5